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7a^2-29a-30=0
a = 7; b = -29; c = -30;
Δ = b2-4ac
Δ = -292-4·7·(-30)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-41}{2*7}=\frac{-12}{14} =-6/7 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+41}{2*7}=\frac{70}{14} =5 $
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